Priniting Reverse tables using Goto Statement in C++

This program prints the multiplication table of a given number in reverse order from the given limit down to 1 using a goto statement. Here's how it works:

The program prompts the user to enter the limit and the number whose multiplication table is to be printed.
The label start marks the beginning of a loop that calculates and prints the multiplication table.
In each iteration of the loop, the program prints the product of the current number (n) and the given number (a).
The variable n is decremented by 1 in each iteration.
The loop continues until n becomes less than or equal to 0.
At this point, the program exits the loop and terminates.

Although this program works correctly, it uses a goto statement, which is generally considered to be bad programming practice. Using goto can make the code harder to read and understand, and can lead to subtle bugs and errors. A better approach would be to use a for or while loop to iterate over the values of n, without using goto. This would make the program more readable and easier to maintain.

Source Code

#include<iostream>
using namespace std;
int main()
{
    int n,a;
    cout<<"\nEnter the limit :";
    cin>>n;
    cout<<"\nEnter the table's number:";
    cin>>a;
    start:
        cout<<"\n"<<n<<"*"<<a<<"="<<n*a;
        n--;
        if(n>0)
        {
            goto start;
        }
    return 0;
}

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Output

Enter the limit :10
Enter the table's number:2
10*2=20
9*2=18
8*2=16
7*2=14
6*2=12
5*2=10
4*2=8
3*2=6
2*2=4
1*2=2

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