Transpose Matrix using Array in C++

The program takes an input matrix from the user, computes the transpose of the matrix, and then prints the transpose. The transpose of a matrix is obtained by interchanging the rows and columns of the original matrix.

Here's how the program works:

The program takes two inputs from the user - the number of rows and the number of columns of the matrix.
The program then takes input from the user for each element of the matrix.
The program then computes the transpose of the matrix by interchanging the rows and columns.
The program then prints the transpose of the matrix.

Overall, the program is correct and should work as expected. However, there is one issue with the program - it assumes that the maximum size of the matrix is 10x10. If the user enters a larger matrix size, the program will not work correctly. To fix this, the program should dynamically allocate memory for the matrix based on the user's input.

Source Code

#include<iostream>
using namespace std;
int main()
{
  int matrix1[10][10],matrix2[10][10],row,col;
  cout<<"\nEnter the number of rows: ";
  cin>>row;
  cout<<"\nEnter the number of columns: ";
  cin>>col;
  cout<<"\nEnter elements of matrix: "<<endl;
  for(int i=0;i<row;i++)
  {
    for(int j=0;j<col;j++)
    {
       cin>>matrix1[i][j];
    }
  }
  for(int i=0;i<row;i++)
  {
    for(int j=0;j<col;j++)
    {
       matrix2[j][i]=matrix1[i][j];
    }
  }
  cout<<"Transpose of Matrix: "<<endl;
  for(int i=0;i<col;i++)
  {
    for(int j=0;j<row;j++)
    {
       cout<<matrix2[i][j]<<" ";
       if(j==row-1)
        cout<<endl;
    }
  }
  return 0;
}

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Output

Enter the number of rows: 2
Enter the number of columns: 2
Enter elements of matrix: 
1
2
3
4
Transpose of Matrix: 
1 3 
2 4

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